A basin with volume 500,000 gal and flow 2 MGD has a detention time of how many hours?

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Prepare for the ADEQ Water Treatment Grade 4 Test. Study with flashcards and multiple-choice questions, with each question offering hints and explanations. Ace your exam!

Multiple Choice

A basin with volume 500,000 gal and flow 2 MGD has a detention time of how many hours?

Explanation:
Detention time is the average time water spends in the basin. It’s found by dividing the basin volume by the flow rate. Here the basin holds 500,000 gallons and the flow is 2 MGD (2,000,000 gallons per day). So, 500,000 / 2,000,000 = 0.25 days. Convert to hours: 0.25 × 24 = 6 hours. The detention time is 6 hours.

Detention time is the average time water spends in the basin. It’s found by dividing the basin volume by the flow rate. Here the basin holds 500,000 gallons and the flow is 2 MGD (2,000,000 gallons per day). So, 500,000 / 2,000,000 = 0.25 days. Convert to hours: 0.25 × 24 = 6 hours. The detention time is 6 hours.

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