A well pump delivering 800 gpm against 150 ft of head with 70% efficiency has a brake horsepower of how many HP?

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Prepare for the ADEQ Water Treatment Grade 4 Test. Study with flashcards and multiple-choice questions, with each question offering hints and explanations. Ace your exam!

Multiple Choice

A well pump delivering 800 gpm against 150 ft of head with 70% efficiency has a brake horsepower of how many HP?

Explanation:
Brake horsepower comes from the shaft power needed to push water up against a head, adjusted by pump efficiency. Start by finding the water horsepower, which is the hydraulic power delivered to the water: WHP = Q × H / 3960. With 800 gpm and 150 ft, WHP ≈ 800 × 150 / 3960 ≈ 30.3 HP. The pump efficiency tells how much of the shaft power becomes water power, so WHP = η × BHP. Rearranging gives BHP = WHP / η = 30.3 / 0.70 ≈ 43.3 HP. Since these calculations are typically rounded to the nearest ten in practice, this is about 40 HP.

Brake horsepower comes from the shaft power needed to push water up against a head, adjusted by pump efficiency. Start by finding the water horsepower, which is the hydraulic power delivered to the water: WHP = Q × H / 3960. With 800 gpm and 150 ft, WHP ≈ 800 × 150 / 3960 ≈ 30.3 HP.

The pump efficiency tells how much of the shaft power becomes water power, so WHP = η × BHP. Rearranging gives BHP = WHP / η = 30.3 / 0.70 ≈ 43.3 HP.

Since these calculations are typically rounded to the nearest ten in practice, this is about 40 HP.

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